# A positively charged rod X is brought near an uncharged metal sphere Y

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**A positively charged rod X is brought near an uncharged metal sphere Y and is then touched by a finger with X still in place. When the finger is removed, the result is that Y has**

**A. no charge and a zero potential.**

**B. a positive charge and a zero potential.**

**C. a negative charge and a positive potential.**

**D. a negative charge and a negative potential.**

**QUICK ANSWER…**

**C**

**EXPLANATION…**

**Please note the following points:**

**Sphere Y was initially neutral.****When positively charged rod, X is brought near it, negative charges will be induced on Y because unlike charges attract each other.****Also, because like charges repel each other, positive charges will be repelled by rod X.****Touching the sphere with a finger while keeping X close will conduct the repelled positive charges out of the sphere into probably the earth.****And the remaining negative charges will leave Y a negatively charged sphere.**

**Please also note that the potential will be positive and not negative because electric potential is a scalar quantity and not a vector quantity, and so a negative sign does not matter.**

**Now for the right answer to the above question:**

**Option A is incorrect. there will be negative charges left.****Option B is incorrect. the charges left will be negative.****C is correct. yes, there will be left over negative charges, and because electric potential is a scalar quantity, the potential will be positive irrespective of the sign of the charge.****D is not the correct answer. No, the potential will be positive and not negative.**

**HELPFUL TIPS…**

**You may please note these/this:**

**Electric potential is a scalar quantity.****Please remember that scalar quantities only have positive magnitudes and no direction; therefore, negativity in sign makes no difference as far as scalars are concerned.**

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**/ culled from 2018 JAMB-UTME physics question 29 /**

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